Distance from Seymour to Civitanova Marche
The shortest distance (air line) between Seymour and Civitanova Marche is 4,859.84 mi (7,821.15 km).
How far is Seymour from Civitanova Marche
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 23:17 (16.03.2025)
Civitanova Marche is located in Macerata, Italy within 43° 17' 60" N 13° 43' 59.88" E (43.3000, 13.7333) coordinates. The local time in Civitanova Marche is 05:17 (17.03.2025)
The calculated flying distance from Civitanova Marche to Civitanova Marche is 4,859.84 miles which is equal to 7,821.15 km.
Seymour, Indiana, United States
Related Distances from Seymour
Civitanova Marche, Macerata, Italy