Distance from Seymour to Civitavecchia
The shortest distance (air line) between Seymour and Civitavecchia is 4,827.31 mi (7,768.80 km).
How far is Seymour from Civitavecchia
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 06:00 (17.03.2025)
Civitavecchia is located in Roma, Italy within 42° 6' 0" N 11° 48' 0" E (42.1000, 11.8000) coordinates. The local time in Civitavecchia is 12:00 (17.03.2025)
The calculated flying distance from Civitavecchia to Civitavecchia is 4,827.31 miles which is equal to 7,768.80 km.
Seymour, Indiana, United States