Distance from Seymour to Diepenbeek
The shortest distance (air line) between Seymour and Diepenbeek is 4,251.39 mi (6,841.96 km).
How far is Seymour from Diepenbeek
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 01:01 (25.02.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 07:01 (25.02.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 4,251.39 miles which is equal to 6,841.96 km.
Seymour, Indiana, United States
Related Distances from Seymour
Diepenbeek, Arr. Hasselt, Belgium