Distance from Seymour to Faches-Thumesnil
The shortest distance (air line) between Seymour and Faches-Thumesnil is 4,169.97 mi (6,710.91 km).
How far is Seymour from Faches-Thumesnil
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 10:26 (28.02.2025)
Faches-Thumesnil is located in Nord, France within 50° 35' 56.04" N 3° 4' 24.96" E (50.5989, 3.0736) coordinates. The local time in Faches-Thumesnil is 16:26 (28.02.2025)
The calculated flying distance from Faches-Thumesnil to Faches-Thumesnil is 4,169.97 miles which is equal to 6,710.91 km.
Seymour, Indiana, United States
Related Distances from Seymour
Faches-Thumesnil, Nord, France