Distance from Seymour to Harelbeke
The shortest distance (air line) between Seymour and Harelbeke is 4,171.38 mi (6,713.19 km).
How far is Seymour from Harelbeke
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 12:28 (05.06.2025)
Harelbeke is located in Arr. Kortrijk, Belgium within 50° 51' 24.12" N 3° 18' 47.16" E (50.8567, 3.3131) coordinates. The local time in Harelbeke is 18:28 (05.06.2025)
The calculated flying distance from Harelbeke to Harelbeke is 4,171.38 miles which is equal to 6,713.19 km.
Seymour, Indiana, United States
Related Distances from Seymour
Harelbeke, Arr. Kortrijk, Belgium