Distance from Seymour to Kalmthout
The shortest distance (air line) between Seymour and Kalmthout is 4,199.67 mi (6,758.71 km).
How far is Seymour from Kalmthout
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 07:18 (26.04.2025)
Kalmthout is located in Arr. Antwerpen, Belgium within 51° 22' 59.88" N 4° 28' 0.12" E (51.3833, 4.4667) coordinates. The local time in Kalmthout is 13:18 (26.04.2025)
The calculated flying distance from Kalmthout to Kalmthout is 4,199.67 miles which is equal to 6,758.71 km.
Seymour, Indiana, United States
Related Distances from Seymour
Kalmthout, Arr. Antwerpen, Belgium