Distance from Seymour to Koekelberg
The shortest distance (air line) between Seymour and Koekelberg is 4,210.76 mi (6,776.57 km).
How far is Seymour from Koekelberg
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 08:40 (25.02.2025)
Koekelberg is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 52' 0.12" N 4° 19' 59.88" E (50.8667, 4.3333) coordinates. The local time in Koekelberg is 14:40 (25.02.2025)
The calculated flying distance from Koekelberg to Koekelberg is 4,210.76 miles which is equal to 6,776.57 km.
Seymour, Indiana, United States
Related Distances from Seymour
Koekelberg, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium