Distance from Seymour to Lampertheim
The shortest distance (air line) between Seymour and Lampertheim is 4,412.99 mi (7,102.02 km).
How far is Seymour from Lampertheim
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 23:27 (08.03.2025)
Lampertheim is located in Bergstraße, Germany within 49° 36' 0" N 8° 28' 0.12" E (49.6000, 8.4667) coordinates. The local time in Lampertheim is 05:27 (09.03.2025)
The calculated flying distance from Lampertheim to Lampertheim is 4,412.99 miles which is equal to 7,102.02 km.
Seymour, Indiana, United States
Related Distances from Seymour
Lampertheim, Bergstraße, Germany