Distance from Seymour to Leopoldshohe
The shortest distance (air line) between Seymour and Leopoldshohe is 4,338.82 mi (6,982.65 km).
How far is Seymour from Leopoldshohe
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 00:52 (09.03.2025)
Leopoldshohe is located in Lippe, Germany within 52° 1' 0.12" N 8° 41' 60" E (52.0167, 8.7000) coordinates. The local time in Leopoldshohe is 06:52 (09.03.2025)
The calculated flying distance from Leopoldshohe to Leopoldshohe is 4,338.82 miles which is equal to 6,982.65 km.
Seymour, Indiana, United States