Distance from Seymour to Lyaskovets
The shortest distance (air line) between Seymour and Lyaskovets is 5,338.68 mi (8,591.78 km).
How far is Seymour from Lyaskovets
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 03:07 (26.02.2025)
Lyaskovets is located in Veliko Tarnovo, Bulgaria within 43° 6' 0" N 25° 43' 0.12" E (43.1000, 25.7167) coordinates. The local time in Lyaskovets is 10:07 (26.02.2025)
The calculated flying distance from Lyaskovets to Lyaskovets is 5,338.68 miles which is equal to 8,591.78 km.
Seymour, Indiana, United States
Related Distances from Seymour
Lyaskovets, Veliko Tarnovo, Bulgaria