Distance from Seymour to Moerdijk
The shortest distance (air line) between Seymour and Moerdijk is 4,196.42 mi (6,753.48 km).
How far is Seymour from Moerdijk
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 10:40 (19.04.2025)
Moerdijk is located in West-Noord-Brabant, Netherlands within 51° 38' 60" N 4° 35' 60" E (51.6500, 4.6000) coordinates. The local time in Moerdijk is 16:40 (19.04.2025)
The calculated flying distance from Moerdijk to Moerdijk is 4,196.42 miles which is equal to 6,753.48 km.
Seymour, Indiana, United States
Related Distances from Seymour
Moerdijk, West-Noord-Brabant, Netherlands