Distance from Seymour to Monte San Savino
The shortest distance (air line) between Seymour and Monte San Savino is 4,776.11 mi (7,686.40 km).
How far is Seymour from Monte San Savino
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 15:54 (18.03.2025)
Monte San Savino is located in Arezzo, Italy within 43° 19' 59.88" N 11° 43' 59.88" E (43.3333, 11.7333) coordinates. The local time in Monte San Savino is 21:54 (18.03.2025)
The calculated flying distance from Monte San Savino to Monte San Savino is 4,776.11 miles which is equal to 7,686.40 km.
Seymour, Indiana, United States
Related Distances from Seymour
Monte San Savino, Arezzo, Italy