Distance from Seymour to Montemor-o-Novo
The shortest distance (air line) between Seymour and Montemor-o-Novo is 4,043.06 mi (6,506.68 km).
How far is Seymour from Montemor-o-Novo
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 11:39 (07.01.2026)
Montemor-o-Novo is located in Alentejo Central, Portugal within 38° 38' 60" N -9° 46' 59.88" W (38.6500, -8.2167) coordinates. The local time in Montemor-o-Novo is 16:39 (07.01.2026)
The calculated flying distance from Montemor-o-Novo to Montemor-o-Novo is 4,043.06 miles which is equal to 6,506.68 km.
Seymour, Indiana, United States
Related Distances from Seymour
Montemor-o-Novo, Alentejo Central, Portugal