Distance from Seymour to Montesarchio
The shortest distance (air line) between Seymour and Montesarchio is 4,987.87 mi (8,027.20 km).
How far is Seymour from Montesarchio
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 15:48 (18.03.2025)
Montesarchio is located in Benevento, Italy within 41° 4' 0.12" N 14° 37' 59.88" E (41.0667, 14.6333) coordinates. The local time in Montesarchio is 21:48 (18.03.2025)
The calculated flying distance from Montesarchio to Montesarchio is 4,987.87 miles which is equal to 8,027.20 km.
Seymour, Indiana, United States
Related Distances from Seymour
Montesarchio, Benevento, Italy