Distance from Seymour to Moortebeek
The shortest distance (air line) between Seymour and Moortebeek is 4,211.35 mi (6,777.51 km).
How far is Seymour from Moortebeek
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 11:30 (25.02.2025)
Moortebeek is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 51' 16.92" N 4° 20' 18.96" E (50.8547, 4.3386) coordinates. The local time in Moortebeek is 17:30 (25.02.2025)
The calculated flying distance from Moortebeek to Moortebeek is 4,211.35 miles which is equal to 6,777.51 km.
Seymour, Indiana, United States
Related Distances from Seymour
Moortebeek, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium