Distance from Seymour to Nieuwkoop
The shortest distance (air line) between Seymour and Nieuwkoop is 4,186.11 mi (6,736.89 km).
How far is Seymour from Nieuwkoop
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 00:42 (20.04.2025)
Nieuwkoop is located in Oost-Zuid-Holland, Netherlands within 52° 10' 59.88" N 4° 46' 0.12" E (52.1833, 4.7667) coordinates. The local time in Nieuwkoop is 06:42 (20.04.2025)
The calculated flying distance from Nieuwkoop to Nieuwkoop is 4,186.11 miles which is equal to 6,736.89 km.
Seymour, Indiana, United States
Related Distances from Seymour
Nieuwkoop, Oost-Zuid-Holland, Netherlands