Distance from Seymour to Oosterzele
The shortest distance (air line) between Seymour and Oosterzele is 4,187.45 mi (6,739.04 km).
How far is Seymour from Oosterzele
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 18:35 (26.04.2025)
Oosterzele is located in Arr. Gent, Belgium within 50° 57' 0" N 3° 47' 60" E (50.9500, 3.8000) coordinates. The local time in Oosterzele is 00:35 (27.04.2025)
The calculated flying distance from Oosterzele to Oosterzele is 4,187.45 miles which is equal to 6,739.04 km.
Seymour, Indiana, United States
Related Distances from Seymour
Oosterzele, Arr. Gent, Belgium