Distance from Seymour to Opglabbeek
The shortest distance (air line) between Seymour and Opglabbeek is 4,253.17 mi (6,844.81 km).
How far is Seymour from Opglabbeek
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 18:10 (26.04.2025)
Opglabbeek is located in Arr. Maaseik, Belgium within 51° 2' 60" N 5° 34' 59.88" E (51.0500, 5.5833) coordinates. The local time in Opglabbeek is 00:10 (27.04.2025)
The calculated flying distance from Opglabbeek to Opglabbeek is 4,253.17 miles which is equal to 6,844.81 km.
Seymour, Indiana, United States
Related Distances from Seymour
Opglabbeek, Arr. Maaseik, Belgium