Distance from Seymour to Oud-Turnhout
The shortest distance (air line) between Seymour and Oud-Turnhout is 4,221.60 mi (6,794.01 km).
How far is Seymour from Oud-Turnhout
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 14:32 (26.04.2025)
Oud-Turnhout is located in Arr. Turnhout, Belgium within 51° 19' 0.12" N 4° 58' 59.88" E (51.3167, 4.9833) coordinates. The local time in Oud-Turnhout is 20:32 (26.04.2025)
The calculated flying distance from Oud-Turnhout to Oud-Turnhout is 4,221.60 miles which is equal to 6,794.01 km.
Seymour, Indiana, United States
Related Distances from Seymour
Oud-Turnhout, Arr. Turnhout, Belgium