Distance from Seymour to Peso da Regua
The shortest distance (air line) between Seymour and Peso da Regua is 3,986.68 mi (6,415.94 km).
How far is Seymour from Peso da Regua
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 06:49 (12.01.2026)
Peso da Regua is located in Douro, Portugal within 41° 9' 55.08" N -8° 13' 24.96" W (41.1653, -7.7764) coordinates. The local time in Peso da Regua is 11:49 (12.01.2026)
The calculated flying distance from Peso da Regua to Peso da Regua is 3,986.68 miles which is equal to 6,415.94 km.
Seymour, Indiana, United States
Related Distances from Seymour
Peso da Regua, Douro, Portugal