Distance from Seymour to Petershagen
The shortest distance (air line) between Seymour and Petershagen is 4,336.25 mi (6,978.52 km).
How far is Seymour from Petershagen
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 10:42 (10.03.2025)
Petershagen is located in Minden-Lübbecke, Germany within 52° 22' 59.88" N 8° 58' 0.12" E (52.3833, 8.9667) coordinates. The local time in Petershagen is 16:42 (10.03.2025)
The calculated flying distance from Petershagen to Petershagen is 4,336.25 miles which is equal to 6,978.52 km.
Seymour, Indiana, United States
Related Distances from Seymour
Petershagen, Minden-Lübbecke, Germany