Distance from Seymour to Ramnicu Valcea
The shortest distance (air line) between Seymour and Ramnicu Valcea is 5,196.98 mi (8,363.72 km).
How far is Seymour from Ramnicu Valcea
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 08:23 (05.01.2026)
Ramnicu Valcea is located in Vâlcea, Romania within 45° 6' 16.92" N 24° 22' 32.16" E (45.1047, 24.3756) coordinates. The local time in Ramnicu Valcea is 15:23 (05.01.2026)
The calculated flying distance from Ramnicu Valcea to Ramnicu Valcea is 5,196.98 miles which is equal to 8,363.72 km.
Seymour, Indiana, United States
Related Distances from Seymour
Ramnicu Valcea, Vâlcea, Romania