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      Distance from Seymour to Rothenburg ob der Tauber

      The shortest distance (air line) between Seymour and Rothenburg ob der Tauber is 4,486.82 mi (7,220.84 km).

      How far is Seymour from Rothenburg ob der Tauber

      Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 17:49 (10.03.2025)

      Rothenburg ob der Tauber is located in Ansbach; Landkreis, Germany within 49° 22' 59.88" N 10° 10' 59.88" E (49.3833, 10.1833) coordinates. The local time in Rothenburg ob der Tauber is 23:49 (10.03.2025)

      The calculated flying distance from Rothenburg ob der Tauber to Rothenburg ob der Tauber is 4,486.82 miles which is equal to 7,220.84 km.

      Seymour, Indiana, United States

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      Rothenburg ob der Tauber, Ansbach; Landkreis, Germany

      Related Distances to Rothenburg ob der Tauber