Distance from Seymour to Saint-Genis-Pouilly
The shortest distance (air line) between Seymour and Saint-Genis-Pouilly is 4,432.04 mi (7,132.68 km).
How far is Seymour from Saint-Genis-Pouilly
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 17:05 (02.03.2025)
Saint-Genis-Pouilly is located in Ain, France within 46° 14' 35.88" N 6° 1' 17.04" E (46.2433, 6.0214) coordinates. The local time in Saint-Genis-Pouilly is 23:05 (02.03.2025)
The calculated flying distance from Saint-Genis-Pouilly to Saint-Genis-Pouilly is 4,432.04 miles which is equal to 7,132.68 km.
Seymour, Indiana, United States
Related Distances from Seymour
Saint-Genis-Pouilly, Ain, France