Distance from Seymour to Sansepolcro
The shortest distance (air line) between Seymour and Sansepolcro is 4,783.61 mi (7,698.47 km).
How far is Seymour from Sansepolcro
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 13:05 (19.03.2025)
Sansepolcro is located in Arezzo, Italy within 43° 34' 32.16" N 12° 8' 38.04" E (43.5756, 12.1439) coordinates. The local time in Sansepolcro is 19:05 (19.03.2025)
The calculated flying distance from Sansepolcro to Sansepolcro is 4,783.61 miles which is equal to 7,698.47 km.
Seymour, Indiana, United States