Distance from Seymour to Sassenberg
The shortest distance (air line) between Seymour and Sassenberg is 4,315.24 mi (6,944.71 km).
How far is Seymour from Sassenberg
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 18:08 (10.03.2025)
Sassenberg is located in Warendorf, Germany within 51° 59' 22.92" N 8° 2' 26.88" E (51.9897, 8.0408) coordinates. The local time in Sassenberg is 00:08 (11.03.2025)
The calculated flying distance from Sassenberg to Sassenberg is 4,315.24 miles which is equal to 6,944.71 km.
Seymour, Indiana, United States
Related Distances from Seymour
Sassenberg, Warendorf, Germany