Distance from Seymour to Sassenheim
The shortest distance (air line) between Seymour and Sassenheim is 4,175.55 mi (6,719.90 km).
How far is Seymour from Sassenheim
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 07:10 (19.04.2025)
Sassenheim is located in Agglomeratie Leiden en Bollenstreek, Netherlands within 52° 13' 32.88" N 4° 31' 21" E (52.2258, 4.5225) coordinates. The local time in Sassenheim is 13:10 (19.04.2025)
The calculated flying distance from Sassenheim to Sassenheim is 4,175.55 miles which is equal to 6,719.90 km.
Seymour, Indiana, United States
Related Distances from Seymour
Sassenheim, Agglomeratie Leiden en Bollenstreek, Netherlands