Distance from Seymour to Sfantu-Gheorghe
The shortest distance (air line) between Seymour and Sfantu-Gheorghe is 5,213.67 mi (8,390.59 km).
How far is Seymour from Sfantu-Gheorghe
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 16:43 (09.01.2026)
Sfantu-Gheorghe is located in Covasna, Romania within 45° 51' 48.96" N 25° 47' 15" E (45.8636, 25.7875) coordinates. The local time in Sfantu-Gheorghe is 23:43 (09.01.2026)
The calculated flying distance from Sfantu-Gheorghe to Sfantu-Gheorghe is 5,213.67 miles which is equal to 8,390.59 km.
Seymour, Indiana, United States
Related Distances from Seymour
Sfantu-Gheorghe, Covasna, Romania