Distance from Seymour to Sint-Andries
The shortest distance (air line) between Seymour and Sint-Andries is 4,155.78 mi (6,688.08 km).
How far is Seymour from Sint-Andries
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 22:53 (26.04.2025)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 04:53 (27.04.2025)
The calculated flying distance from Sint-Andries to Sint-Andries is 4,155.78 miles which is equal to 6,688.08 km.
Seymour, Indiana, United States
Related Distances from Seymour
Sint-Andries, Arr. Brugge, Belgium