Distance from Seymour to Sint Anthonis
The shortest distance (air line) between Seymour and Sint Anthonis is 4,245.98 mi (6,833.25 km).
How far is Seymour from Sint Anthonis
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 00:46 (19.04.2025)
Sint Anthonis is located in Noordoost-Noord-Brabant, Netherlands within 51° 37' 32.88" N 5° 52' 51.96" E (51.6258, 5.8811) coordinates. The local time in Sint Anthonis is 06:46 (19.04.2025)
The calculated flying distance from Sint Anthonis to Sint Anthonis is 4,245.98 miles which is equal to 6,833.25 km.
Seymour, Indiana, United States
Related Distances from Seymour
Sint Anthonis, Noordoost-Noord-Brabant, Netherlands