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      Distance from Seymour to Sint-Genesius-Rode

      The shortest distance (air line) between Seymour and Sint-Genesius-Rode is 4,215.12 mi (6,783.57 km).

      How far is Seymour from Sint-Genesius-Rode

      Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 14:21 (25.02.2025)

      Sint-Genesius-Rode is located in Arr. Halle-Vilvoorde, Belgium within 50° 44' 42" N 4° 20' 47.04" E (50.7450, 4.3464) coordinates. The local time in Sint-Genesius-Rode is 20:21 (25.02.2025)

      The calculated flying distance from Sint-Genesius-Rode to Sint-Genesius-Rode is 4,215.12 miles which is equal to 6,783.57 km.

      Seymour, Indiana, United States

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      Sint-Genesius-Rode, Arr. Halle-Vilvoorde, Belgium

      Related Distances to Sint-Genesius-Rode