Distance from Seymour to Sint-Kruis
The shortest distance (air line) between Seymour and Sint-Kruis is 4,158.01 mi (6,691.67 km).
How far is Seymour from Sint-Kruis
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 23:21 (26.04.2025)
Sint-Kruis is located in Arr. Brugge, Belgium within 51° 12' 42.12" N 3° 15' 0" E (51.2117, 3.2500) coordinates. The local time in Sint-Kruis is 05:21 (27.04.2025)
The calculated flying distance from Sint-Kruis to Sint-Kruis is 4,158.01 miles which is equal to 6,691.67 km.
Seymour, Indiana, United States
Related Distances from Seymour
Sint-Kruis, Arr. Brugge, Belgium