Distance from Seymour to Steenokkerzeel
The shortest distance (air line) between Seymour and Steenokkerzeel is 4,215.90 mi (6,784.83 km).
How far is Seymour from Steenokkerzeel
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 17:19 (25.02.2025)
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 23:19 (25.02.2025)
The calculated flying distance from Steenokkerzeel to Steenokkerzeel is 4,215.90 miles which is equal to 6,784.83 km.
Seymour, Indiana, United States
Related Distances from Seymour
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium