Distance from Seymour to Terneuzen
The shortest distance (air line) between Seymour and Terneuzen is 4,176.83 mi (6,721.96 km).
How far is Seymour from Terneuzen
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 04:46 (19.04.2025)
Terneuzen is located in Zeeuwsch-Vlaanderen, Netherlands within 51° 19' 59.88" N 3° 49' 59.88" E (51.3333, 3.8333) coordinates. The local time in Terneuzen is 10:46 (19.04.2025)
The calculated flying distance from Terneuzen to Terneuzen is 4,176.83 miles which is equal to 6,721.96 km.
Seymour, Indiana, United States
Related Distances from Seymour
Terneuzen, Zeeuwsch-Vlaanderen, Netherlands