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      Distance from Seymour to Villeneuve-les-Maguelone

      The shortest distance (air line) between Seymour and Villeneuve-les-Maguelone is 4,435.03 mi (7,137.49 km).

      How far is Seymour from Villeneuve-les-Maguelone

      Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 23:35 (03.03.2025)

      Villeneuve-les-Maguelone is located in Hérault, France within 43° 31' 55.92" N 3° 51' 38.88" E (43.5322, 3.8608) coordinates. The local time in Villeneuve-les-Maguelone is 05:35 (04.03.2025)

      The calculated flying distance from Villeneuve-les-Maguelone to Villeneuve-les-Maguelone is 4,435.03 miles which is equal to 7,137.49 km.

      Seymour, Indiana, United States

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      Villeneuve-les-Maguelone, Hérault, France

      Related Distances to Villeneuve-les-Maguelone