Distance from Seymour to Waalwijk
The shortest distance (air line) between Seymour and Waalwijk is 4,213.18 mi (6,780.46 km).
How far is Seymour from Waalwijk
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 07:52 (12.06.2025)
Waalwijk is located in Midden-Noord-Brabant, Netherlands within 51° 40' 59.88" N 5° 4' 0.12" E (51.6833, 5.0667) coordinates. The local time in Waalwijk is 13:52 (12.06.2025)
The calculated flying distance from Waalwijk to Waalwijk is 4,213.18 miles which is equal to 6,780.46 km.
Seymour, Indiana, United States
Related Distances from Seymour
Waalwijk, Midden-Noord-Brabant, Netherlands