Distance from Seymour to Waddinxveen
The shortest distance (air line) between Seymour and Waddinxveen is 4,185.84 mi (6,736.45 km).
How far is Seymour from Waddinxveen
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 01:39 (22.04.2025)
Waddinxveen is located in Oost-Zuid-Holland, Netherlands within 52° 2' 60" N 4° 39' 0" E (52.0500, 4.6500) coordinates. The local time in Waddinxveen is 07:39 (22.04.2025)
The calculated flying distance from Waddinxveen to Waddinxveen is 4,185.84 miles which is equal to 6,736.45 km.
Seymour, Indiana, United States
Related Distances from Seymour
Waddinxveen, Oost-Zuid-Holland, Netherlands