Distance from Seymour to Wittenheim
The shortest distance (air line) between Seymour and Wittenheim is 4,431.00 mi (7,131.01 km).
How far is Seymour from Wittenheim
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 00:07 (04.03.2025)
Wittenheim is located in Haut-Rhin, France within 47° 48' 27" N 7° 20' 12.84" E (47.8075, 7.3369) coordinates. The local time in Wittenheim is 06:07 (04.03.2025)
The calculated flying distance from Wittenheim to Wittenheim is 4,431.00 miles which is equal to 7,131.01 km.
Seymour, Indiana, United States