Distance from Seymour to Wommelgem
The shortest distance (air line) between Seymour and Wommelgem is 4,207.35 mi (6,771.08 km).
How far is Seymour from Wommelgem
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 00:54 (26.02.2025)
Wommelgem is located in Arr. Antwerpen, Belgium within 51° 12' 0" N 4° 31' 0.12" E (51.2000, 4.5167) coordinates. The local time in Wommelgem is 06:54 (26.02.2025)
The calculated flying distance from Wommelgem to Wommelgem is 4,207.35 miles which is equal to 6,771.08 km.
Seymour, Indiana, United States
Related Distances from Seymour
Wommelgem, Arr. Antwerpen, Belgium