Distance from Seymour to Wuustwezel
The shortest distance (air line) between Seymour and Wuustwezel is 4,204.79 mi (6,766.95 km).
How far is Seymour from Wuustwezel
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 07:12 (27.04.2025)
Wuustwezel is located in Arr. Antwerpen, Belgium within 51° 22' 59.88" N 4° 35' 60" E (51.3833, 4.6000) coordinates. The local time in Wuustwezel is 13:12 (27.04.2025)
The calculated flying distance from Wuustwezel to Wuustwezel is 4,204.79 miles which is equal to 6,766.95 km.
Seymour, Indiana, United States
Related Distances from Seymour
Wuustwezel, Arr. Antwerpen, Belgium