Distance from Seymour to Zonnebeke
The shortest distance (air line) between Seymour and Zonnebeke is 4,158.20 mi (6,691.97 km).
How far is Seymour from Zonnebeke
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 08:55 (27.04.2025)
Zonnebeke is located in Arr. Ieper, Belgium within 50° 52' 0.12" N 2° 58' 59.88" E (50.8667, 2.9833) coordinates. The local time in Zonnebeke is 14:55 (27.04.2025)
The calculated flying distance from Zonnebeke to Zonnebeke is 4,158.20 miles which is equal to 6,691.97 km.
Seymour, Indiana, United States
Related Distances from Seymour
Zonnebeke, Arr. Ieper, Belgium