Distance from Shakopee to Dimitrovgrad
The shortest distance (air line) between Shakopee and Dimitrovgrad is 5,214.64 mi (8,392.15 km).
How far is Shakopee from Dimitrovgrad
Shakopee is located in Minnesota, United States within 44° 46' 28.2" N -94° 31' 22.08" W (44.7745, -93.4772) coordinates. The local time in Shakopee is 01:38 (25.04.2025)
Dimitrovgrad is located in Pirotska oblast, Serbia within 43° 1' 0.12" N 22° 46' 59.88" E (43.0167, 22.7833) coordinates. The local time in Dimitrovgrad is 08:38 (25.04.2025)
The calculated flying distance from Dimitrovgrad to Dimitrovgrad is 5,214.64 miles which is equal to 8,392.15 km.
Shakopee, Minnesota, United States
Related Distances from Shakopee
Dimitrovgrad, Pirotska oblast, Serbia