Distance from Shakopee to Quincy-sous-Senart
The shortest distance (air line) between Shakopee and Quincy-sous-Senart is 4,237.32 mi (6,819.31 km).
How far is Shakopee from Quincy-sous-Senart
Shakopee is located in Minnesota, United States within 44° 46' 28.2" N -94° 31' 22.08" W (44.7745, -93.4772) coordinates. The local time in Shakopee is 01:45 (01.05.2025)
Quincy-sous-Senart is located in Essonne, France within 48° 40' 15.96" N 2° 32' 2.04" E (48.6711, 2.5339) coordinates. The local time in Quincy-sous-Senart is 08:45 (01.05.2025)
The calculated flying distance from Quincy-sous-Senart to Quincy-sous-Senart is 4,237.32 miles which is equal to 6,819.31 km.
Shakopee, Minnesota, United States
Related Distances from Shakopee
Quincy-sous-Senart, Essonne, France