Distance from Shenfield to Tomaszow Lubelski
The shortest distance (air line) between Shenfield and Tomaszow Lubelski is 1,002.55 mi (1,613.45 km).
How far is Shenfield from Tomaszow Lubelski
Shenfield is located in Heart of Essex, United Kingdom within 51° 37' 46.92" N 0° 19' 9.12" E (51.6297, 0.3192) coordinates. The local time in Shenfield is 17:36 (27.02.2025)
Tomaszow Lubelski is located in Chełmsko-zamojski, Poland within 50° 27' 0" N 23° 25' 0.12" E (50.4500, 23.4167) coordinates. The local time in Tomaszow Lubelski is 18:36 (27.02.2025)
The calculated flying distance from Tomaszow Lubelski to Tomaszow Lubelski is 1,002.55 miles which is equal to 1,613.45 km.
Shenfield, Heart of Essex, United Kingdom
Related Distances from Shenfield
Tomaszow Lubelski, Chełmsko-zamojski, Poland