Distance from Shively to Waldshut-Tiengen
The shortest distance (air line) between Shively and Waldshut-Tiengen is 4,504.25 mi (7,248.89 km).
How far is Shively from Waldshut-Tiengen
Shively is located in Kentucky, United States within 38° 11' 49.2" N -86° 11' 11.04" W (38.1970, -85.8136) coordinates. The local time in Shively is 12:32 (11.03.2025)
Waldshut-Tiengen is located in Waldshut, Germany within 47° 37' 23.16" N 8° 12' 51.84" E (47.6231, 8.2144) coordinates. The local time in Waldshut-Tiengen is 18:32 (11.03.2025)
The calculated flying distance from Waldshut-Tiengen to Waldshut-Tiengen is 4,504.25 miles which is equal to 7,248.89 km.
Shively, Kentucky, United States
Related Distances from Shively
Waldshut-Tiengen, Waldshut, Germany