Distance from Sidney to Celakovice
The shortest distance (air line) between Sidney and Celakovice is 4,499.10 mi (7,240.60 km).
How far is Sidney from Celakovice
Sidney is located in Ohio, United States within 40° 17' 20.76" N -85° 49' 59.88" W (40.2891, -84.1667) coordinates. The local time in Sidney is 04:22 (28.02.2025)
Celakovice is located in Středočeský kraj, Czechia within 50° 9' 38.16" N 14° 45' 0" E (50.1606, 14.7500) coordinates. The local time in Celakovice is 10:22 (28.02.2025)
The calculated flying distance from Celakovice to Celakovice is 4,499.10 miles which is equal to 7,240.60 km.
Related Distances from Sidney
Celakovice, Středočeský kraj, Czechia