Distance from Sidney to Steenokkerzeel
The shortest distance (air line) between Sidney and Steenokkerzeel is 4,085.54 mi (6,575.04 km).
How far is Sidney from Steenokkerzeel
Sidney is located in Ohio, United States within 40° 17' 20.76" N -85° 49' 59.88" W (40.2891, -84.1667) coordinates. The local time in Sidney is 08:21 (27.02.2025)
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 14:21 (27.02.2025)
The calculated flying distance from Steenokkerzeel to Steenokkerzeel is 4,085.54 miles which is equal to 6,575.04 km.
Related Distances from Sidney
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium