Distance from Simpelveld to Jefferson
The shortest distance (air line) between Simpelveld and Jefferson is 4,419.77 mi (7,112.94 km).
How far is Simpelveld from Jefferson
Simpelveld is located in Zuid-Limburg, Netherlands within 50° 49' 59.88" N 5° 58' 59.88" E (50.8333, 5.9833) coordinates. The local time in Simpelveld is 10:29 (24.12.2025)
Jefferson is located in Georgia, United States within 34° 8' 14.28" N -84° 23' 52.44" W (34.1373, -83.6021) coordinates. The local time in Jefferson is 04:29 (24.12.2025)
The calculated flying distance from Jefferson to Jefferson is 4,419.77 miles which is equal to 7,112.94 km.
Simpelveld, Zuid-Limburg, Netherlands
Related Distances from Simpelveld
Jefferson, Georgia, United States