Distance from Simpelveld to Jefferson Hills
The shortest distance (air line) between Simpelveld and Jefferson Hills is 3,980.39 mi (6,405.83 km).
How far is Simpelveld from Jefferson Hills
Simpelveld is located in Zuid-Limburg, Netherlands within 50° 49' 59.88" N 5° 58' 59.88" E (50.8333, 5.9833) coordinates. The local time in Simpelveld is 11:54 (24.12.2025)
Jefferson Hills is located in Pennsylvania, United States within 40° 17' 33.36" N -80° 4' 1.56" W (40.2926, -79.9329) coordinates. The local time in Jefferson Hills is 05:54 (24.12.2025)
The calculated flying distance from Jefferson Hills to Jefferson Hills is 3,980.39 miles which is equal to 6,405.83 km.
Simpelveld, Zuid-Limburg, Netherlands
Related Distances from Simpelveld
Jefferson Hills, Pennsylvania, United States