Distance from Simpelveld to Martinsville
The shortest distance (air line) between Simpelveld and Martinsville is 4,146.34 mi (6,672.88 km).
How far is Simpelveld from Martinsville
Simpelveld is located in Zuid-Limburg, Netherlands within 50° 49' 59.88" N 5° 58' 59.88" E (50.8333, 5.9833) coordinates. The local time in Simpelveld is 05:41 (06.01.2026)
Martinsville is located in Virginia, United States within 36° 40' 57.36" N -80° 8' 11.04" W (36.6826, -79.8636) coordinates. The local time in Martinsville is 23:41 (05.01.2026)
The calculated flying distance from Martinsville to Martinsville is 4,146.34 miles which is equal to 6,672.88 km.
Simpelveld, Zuid-Limburg, Netherlands
Related Distances from Simpelveld
Martinsville, Virginia, United States